rcu: Assume rcu_report_dead() is always called locally

rcu_report_dead() has to be called locally by the CPU that is going to
exit the RCU state machine. Passing a cpu argument here is error-prone
and leaves the possibility for a racy remote call.

Use local access instead.

Reviewed-by: Paul E. McKenney <paulmck@kernel.org>
Signed-off-by: Frederic Weisbecker <frederic@kernel.org>
This commit is contained in:
Frederic Weisbecker
2023-09-08 22:35:59 +02:00
parent 358662a961
commit c964c1f5ee
4 changed files with 5 additions and 5 deletions
+1 -1
View File
@@ -122,7 +122,7 @@ static inline void call_rcu_hurry(struct rcu_head *head, rcu_callback_t func)
void rcu_init(void);
extern int rcu_scheduler_active;
void rcu_sched_clock_irq(int user);
void rcu_report_dead(unsigned int cpu);
void rcu_report_dead(void);
void rcutree_migrate_callbacks(int cpu);
#ifdef CONFIG_TASKS_RCU_GENERIC